Base | Representation |
---|---|
bin | 10100100011000010011… |
… | …011101100100011001011 |
3 | 11222222122111101201211110 |
4 | 110203002123230203023 |
5 | 141113244344011410 |
6 | 3000400302501403 |
7 | 204004646063226 |
oct | 24430233544313 |
9 | 4888574351743 |
10 | 1412011313355 |
11 | 4a4915636845 |
12 | 1a97a7894863 |
13 | a31c91ccc96 |
14 | 4c4ad9305bd |
15 | 26ae28b7720 |
hex | 148c26ec8cb |
1412011313355 has 16 divisors (see below), whose sum is σ = 2272746357504. Its totient is φ = 748563281760.
The previous prime is 1412011313351. The next prime is 1412011313393. The reversal of 1412011313355 is 5533131102141.
It is not a de Polignac number, because 1412011313355 - 22 = 1412011313351 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1412011313351) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 281836081 + ... + 281841090.
It is an arithmetic number, because the mean of its divisors is an integer number (142046647344).
Almost surely, 21412011313355 is an apocalyptic number.
1412011313355 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1412011313355 is a deficient number, since it is larger than the sum of its proper divisors (860735044149).
1412011313355 is a wasteful number, since it uses less digits than its factorization.
1412011313355 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 563677346.
The product of its (nonzero) digits is 5400, while the sum is 30.
Adding to 1412011313355 its reverse (5533131102141), we get a palindrome (6945142415496).
The spelling of 1412011313355 in words is "one trillion, four hundred twelve billion, eleven million, three hundred thirteen thousand, three hundred fifty-five".
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