Base | Representation |
---|---|
bin | 1100110101111001100001… |
… | …1010101100001001100101 |
3 | 1211222212111001210122102020 |
4 | 3031132120122230021211 |
5 | 3322320443321312430 |
6 | 50010405140333353 |
7 | 2655100414041624 |
oct | 315363032541145 |
9 | 54885431718366 |
10 | 14120114635365 |
11 | 4554341667a82 |
12 | 17006a59a4259 |
13 | 7b56a0b0749b |
14 | 36b5baad56bb |
15 | 19746ae99b10 |
hex | cd7986ac265 |
14120114635365 has 16 divisors (see below), whose sum is σ = 22592517000000. Its totient is φ = 7530616611072.
The previous prime is 14120114635357. The next prime is 14120114635441. The reversal of 14120114635365 is 56353641102141.
14120114635365 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 14120114635365 - 23 = 14120114635357 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5894740 + ... + 7936509.
It is an arithmetic number, because the mean of its divisors is an integer number (1412032312500).
Almost surely, 214120114635365 is an apocalyptic number.
14120114635365 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
14120114635365 is a deficient number, since it is larger than the sum of its proper divisors (8472402364635).
14120114635365 is a wasteful number, since it uses less digits than its factorization.
14120114635365 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13899316.
The product of its (nonzero) digits is 259200, while the sum is 42.
The spelling of 14120114635365 in words is "fourteen trillion, one hundred twenty billion, one hundred fourteen million, six hundred thirty-five thousand, three hundred sixty-five".
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