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14120121444223 = 108712989992129
BaseRepresentation
bin1100110101111001100011…
…0100101010011101111111
31211222212111112121120102011
43031132120310222131333
53322321002042203343
650010405542312051
72655100525650544
oct315363064523577
954885445546364
1014120121444223
114554345498633
1217006a8128627
137b56a234c6b2
1436b5bb988bcb
1519746b89229d
hexcd798d2a77f

14120121444223 has 4 divisors (see below), whose sum is σ = 14133111437440. Its totient is φ = 14107131451008.

The previous prime is 14120121444193. The next prime is 14120121444229. The reversal of 14120121444223 is 32244412102141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14120121444223 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14120121444229) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6494994978 + ... + 6494997151.

It is an arithmetic number, because the mean of its divisors is an integer number (3533277859360).

Almost surely, 214120121444223 is an apocalyptic number.

14120121444223 is a deficient number, since it is larger than the sum of its proper divisors (12989993217).

14120121444223 is a wasteful number, since it uses less digits than its factorization.

14120121444223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12989993216.

The product of its (nonzero) digits is 12288, while the sum is 31.

Adding to 14120121444223 its reverse (32244412102141), we get a palindrome (46364533546364).

The spelling of 14120121444223 in words is "fourteen trillion, one hundred twenty billion, one hundred twenty-one million, four hundred forty-four thousand, two hundred twenty-three".

Divisors: 1 1087 12989992129 14120121444223