Base | Representation |
---|---|
bin | 1100110101111001100011… |
… | …0100101010011101111111 |
3 | 1211222212111112121120102011 |
4 | 3031132120310222131333 |
5 | 3322321002042203343 |
6 | 50010405542312051 |
7 | 2655100525650544 |
oct | 315363064523577 |
9 | 54885445546364 |
10 | 14120121444223 |
11 | 4554345498633 |
12 | 17006a8128627 |
13 | 7b56a234c6b2 |
14 | 36b5bb988bcb |
15 | 19746b89229d |
hex | cd798d2a77f |
14120121444223 has 4 divisors (see below), whose sum is σ = 14133111437440. Its totient is φ = 14107131451008.
The previous prime is 14120121444193. The next prime is 14120121444229. The reversal of 14120121444223 is 32244412102141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14120121444223 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14120121444229) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6494994978 + ... + 6494997151.
It is an arithmetic number, because the mean of its divisors is an integer number (3533277859360).
Almost surely, 214120121444223 is an apocalyptic number.
14120121444223 is a deficient number, since it is larger than the sum of its proper divisors (12989993217).
14120121444223 is a wasteful number, since it uses less digits than its factorization.
14120121444223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12989993216.
The product of its (nonzero) digits is 12288, while the sum is 31.
Adding to 14120121444223 its reverse (32244412102141), we get a palindrome (46364533546364).
The spelling of 14120121444223 in words is "fourteen trillion, one hundred twenty billion, one hundred twenty-one million, four hundred forty-four thousand, two hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •