Base | Representation |
---|---|
bin | 100000000110101111111001… |
… | …111011101101001011100101 |
3 | 200111221201002101221100010120 |
4 | 200012233321323231023211 |
5 | 122001420121204044331 |
6 | 1220150542222112153 |
7 | 41512311301434000 |
oct | 4006577173551345 |
9 | 614851071840116 |
10 | 141201243034341 |
11 | 40a9a124647446 |
12 | 13a058b671b659 |
13 | 60a32b26a9589 |
14 | 26c2268948537 |
15 | 114ce7d3b3796 |
hex | 806bf9eed2e5 |
141201243034341 has 16 divisors (see below), whose sum is σ = 219554896848000. Its totient is φ = 80686424590464.
The previous prime is 141201243034321. The next prime is 141201243034363. The reversal of 141201243034341 is 143430342102141.
It is a happy number.
It is not a de Polignac number, because 141201243034341 - 25 = 141201243034309 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (141201243034321) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 68610904236 + ... + 68610906293.
It is an arithmetic number, because the mean of its divisors is an integer number (13722181053000).
Almost surely, 2141201243034341 is an apocalyptic number.
It is an amenable number.
141201243034341 is a deficient number, since it is larger than the sum of its proper divisors (78353653813659).
141201243034341 is an equidigital number, since it uses as much as digits as its factorization.
141201243034341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 137221810553 (or 137221810539 counting only the distinct ones).
The product of its (nonzero) digits is 27648, while the sum is 33.
Adding to 141201243034341 its reverse (143430342102141), we get a palindrome (284631585136482).
The spelling of 141201243034341 in words is "one hundred forty-one trillion, two hundred one billion, two hundred forty-three million, thirty-four thousand, three hundred forty-one".
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