Base | Representation |
---|---|
bin | 100000000110101111111001… |
… | …111011111101110010000101 |
3 | 200111221201002102001210102002 |
4 | 200012233321323331302011 |
5 | 122001420121213233331 |
6 | 1220150542223355045 |
7 | 41512311302136152 |
oct | 4006577173756205 |
9 | 614851072053362 |
10 | 141201243102341 |
11 | 40a9a124693544 |
12 | 13a058b6752a85 |
13 | 60a32b2701506 |
14 | 26c2268965229 |
15 | 114ce7d3c89cb |
hex | 806bf9efdc85 |
141201243102341 has 2 divisors, whose sum is σ = 141201243102342. Its totient is φ = 141201243102340.
The previous prime is 141201243102329. The next prime is 141201243102383. The reversal of 141201243102341 is 143201342102141.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 135770175986116 + 5431067116225 = 11652046^2 + 2330465^2 .
It is a cyclic number.
It is not a de Polignac number, because 141201243102341 - 218 = 141201242840197 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (141201243102301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70600621551170 + 70600621551171.
It is an arithmetic number, because the mean of its divisors is an integer number (70600621551171).
Almost surely, 2141201243102341 is an apocalyptic number.
It is an amenable number.
141201243102341 is a deficient number, since it is larger than the sum of its proper divisors (1).
141201243102341 is an equidigital number, since it uses as much as digits as its factorization.
141201243102341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4608, while the sum is 29.
Adding to 141201243102341 its reverse (143201342102141), we get a palindrome (284402585204482).
The spelling of 141201243102341 in words is "one hundred forty-one trillion, two hundred one billion, two hundred forty-three million, one hundred two thousand, three hundred forty-one".
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