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141201243102341 is a prime number
BaseRepresentation
bin100000000110101111111001…
…111011111101110010000101
3200111221201002102001210102002
4200012233321323331302011
5122001420121213233331
61220150542223355045
741512311302136152
oct4006577173756205
9614851072053362
10141201243102341
1140a9a124693544
1213a058b6752a85
1360a32b2701506
1426c2268965229
15114ce7d3c89cb
hex806bf9efdc85

141201243102341 has 2 divisors, whose sum is σ = 141201243102342. Its totient is φ = 141201243102340.

The previous prime is 141201243102329. The next prime is 141201243102383. The reversal of 141201243102341 is 143201342102141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 135770175986116 + 5431067116225 = 11652046^2 + 2330465^2 .

It is a cyclic number.

It is not a de Polignac number, because 141201243102341 - 218 = 141201242840197 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141201243102301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70600621551170 + 70600621551171.

It is an arithmetic number, because the mean of its divisors is an integer number (70600621551171).

Almost surely, 2141201243102341 is an apocalyptic number.

It is an amenable number.

141201243102341 is a deficient number, since it is larger than the sum of its proper divisors (1).

141201243102341 is an equidigital number, since it uses as much as digits as its factorization.

141201243102341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 141201243102341 its reverse (143201342102141), we get a palindrome (284402585204482).

The spelling of 141201243102341 in words is "one hundred forty-one trillion, two hundred one billion, two hundred forty-three million, one hundred two thousand, three hundred forty-one".