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14120201333 = 72017171619
BaseRepresentation
bin11010010011010000…
…10010110001110101
31100110001122112210202
431021220102301311
5212404232420313
610253044530245
71006624505510
oct151150226165
940401575722
1014120201333
115a96538287
1228a09b0985
1314404a6624
1497d445d77
15579978558
hex349a12c75

14120201333 has 4 divisors (see below), whose sum is σ = 16137372960. Its totient is φ = 12103029708.

The previous prime is 14120201323. The next prime is 14120201341. The reversal of 14120201333 is 33310202141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33310202141 = 221315052057.

It is not a de Polignac number, because 14120201333 - 26 = 14120201269 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14120201323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1008585803 + ... + 1008585816.

It is an arithmetic number, because the mean of its divisors is an integer number (4034343240).

Almost surely, 214120201333 is an apocalyptic number.

It is an amenable number.

14120201333 is a deficient number, since it is larger than the sum of its proper divisors (2017171627).

14120201333 is an equidigital number, since it uses as much as digits as its factorization.

14120201333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2017171626.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 14120201333 its reverse (33310202141), we get a palindrome (47430403474).

The spelling of 14120201333 in words is "fourteen billion, one hundred twenty million, two hundred one thousand, three hundred thirty-three".

Divisors: 1 7 2017171619 14120201333