14120211024541 has 4 divisors (see below), whose sum is σ = 14575701702784. Its totient is φ = 13664720346300.

The previous prime is 14120211024509. The next prime is 14120211024587. The reversal of 14120211024541 is 14542011202141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14120211024541 - 2⁵ = 14120211024509 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14120211024341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 227745339075 + ... + 227745339136.

It is an arithmetic number, because the mean of its divisors is an integer number (3643925425696).

Almost surely, 2^{14120211024541} is an apocalyptic number.

It is an amenable number.

14120211024541 is a deficient number, since it is larger than the sum of its proper divisors (455490678243).

14120211024541 is an equidigital number, since it uses as much as digits as its factorization.

14120211024541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 455490678242.

The product of its (nonzero) digits is 2560, while the sum is 28.

Adding to 14120211024541 its reverse (14542011202141), we get a palindrome (28662222226682).

The spelling of 14120211024541 in words is "fourteen trillion, one hundred twenty billion, two hundred eleven million, twenty-four thousand, five hundred forty-one".