14120221323421 has 4 divisors (see below), whose sum is σ = 14120242454812. Its totient is φ = 14120200192032.

The previous prime is 14120221323391. The next prime is 14120221323431. The reversal of 14120221323421 is 12432312202141.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7326306091225 + 6793915232196 = 2706715^2 + 2606514^2 .

It is a cyclic number.

It is not a de Polignac number, because 14120221323421 - 2⁷ = 14120221323293 is a prime.

It is a super-3 number, since 3×14120221323421³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14120221323421.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14120221323431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9529506 + ... + 10911091.

It is an arithmetic number, because the mean of its divisors is an integer number (3530060613703).

Almost surely, 2^{14120221323421} is an apocalyptic number.

It is an amenable number.

14120221323421 is a deficient number, since it is larger than the sum of its proper divisors (21131391).

14120221323421 is an equidigital number, since it uses as much as digits as its factorization.

14120221323421 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21131390.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 14120221323421 its reverse (12432312202141), we get a palindrome (26552533525562).

The spelling of 14120221323421 in words is "fourteen trillion, one hundred twenty billion, two hundred twenty-one million, three hundred twenty-three thousand, four hundred twenty-one".