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14120223341453 is a prime number
BaseRepresentation
bin1100110101111001111011…
…1001010111101110001101
31211222212202122100111010122
43031132132321113232031
53322321204133411303
650010424022314325
72655103204034165
oct315363671275615
954885678314118
1014120223341453
114554397a65519
1217007162889a5
137b56ba4a8908
1436b5cb3115a5
151974757bde38
hexcd79ee57b8d

14120223341453 has 2 divisors, whose sum is σ = 14120223341454. Its totient is φ = 14120223341452.

The previous prime is 14120223341429. The next prime is 14120223341479. The reversal of 14120223341453 is 35414332202141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13946915986249 + 173307355204 = 3734557^2 + 416302^2 .

It is a cyclic number.

It is not a de Polignac number, because 14120223341453 - 214 = 14120223325069 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14120223341953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7060111670726 + 7060111670727.

It is an arithmetic number, because the mean of its divisors is an integer number (7060111670727).

Almost surely, 214120223341453 is an apocalyptic number.

It is an amenable number.

14120223341453 is a deficient number, since it is larger than the sum of its proper divisors (1).

14120223341453 is an equidigital number, since it uses as much as digits as its factorization.

14120223341453 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 69120, while the sum is 35.

Adding to 14120223341453 its reverse (35414332202141), we get a palindrome (49534555543594).

The spelling of 14120223341453 in words is "fourteen trillion, one hundred twenty billion, two hundred twenty-three million, three hundred forty-one thousand, four hundred fifty-three".