Base | Representation |
---|---|
bin | 100000000110110000110101… |
… | …100111100111110001000010 |
3 | 200111221210200012012002122121 |
4 | 200012300311213213301002 |
5 | 122001424144031332432 |
6 | 1220151225432554454 |
7 | 41512345151062642 |
oct | 4006606547476102 |
9 | 614853605162577 |
10 | 141202244402242 |
11 | 40a9a598914a21 |
12 | 13a05b35b52a2a |
13 | 60a3411ca526a |
14 | 26c2321930522 |
15 | 114cedb265197 |
hex | 806c359e7c42 |
141202244402242 has 4 divisors (see below), whose sum is σ = 211803366603366. Its totient is φ = 70601122201120.
The previous prime is 141202244402239. The next prime is 141202244402243. The reversal of 141202244402242 is 242204442202141.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 124813114776441 + 16389129625801 = 11171979^2 + 4048349^2 .
It is a junction number, because it is equal to n+sod(n) for n = 141202244402198 and 141202244402207.
It is not an unprimeable number, because it can be changed into a prime (141202244402243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35300561100559 + ... + 35300561100562.
Almost surely, 2141202244402242 is an apocalyptic number.
141202244402242 is a deficient number, since it is larger than the sum of its proper divisors (70601122201124).
141202244402242 is an equidigital number, since it uses as much as digits as its factorization.
141202244402242 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 70601122201123.
The product of its (nonzero) digits is 65536, while the sum is 34.
Adding to 141202244402242 its reverse (242204442202141), we get a palindrome (383406686604383).
The spelling of 141202244402242 in words is "one hundred forty-one trillion, two hundred two billion, two hundred forty-four million, four hundred two thousand, two hundred forty-two".
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