Base | Representation |
---|---|
bin | 100000000110110000110101… |
… | …100111100111110001000011 |
3 | 200111221210200012012002122122 |
4 | 200012300311213213301003 |
5 | 122001424144031332433 |
6 | 1220151225432554455 |
7 | 41512345151062643 |
oct | 4006606547476103 |
9 | 614853605162578 |
10 | 141202244402243 |
11 | 40a9a598914a22 |
12 | 13a05b35b52a2b |
13 | 60a3411ca526b |
14 | 26c2321930523 |
15 | 114cedb265198 |
hex | 806c359e7c43 |
141202244402243 has 2 divisors, whose sum is σ = 141202244402244. Its totient is φ = 141202244402242.
The previous prime is 141202244402239. The next prime is 141202244402273. The reversal of 141202244402243 is 342204442202141.
It is a weak prime.
It is an emirp because it is prime and its reverse (342204442202141) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 141202244402243 - 22 = 141202244402239 is a prime.
It is not a weakly prime, because it can be changed into another prime (141202244402273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70601122201121 + 70601122201122.
It is an arithmetic number, because the mean of its divisors is an integer number (70601122201122).
Almost surely, 2141202244402243 is an apocalyptic number.
141202244402243 is a deficient number, since it is larger than the sum of its proper divisors (1).
141202244402243 is an equidigital number, since it uses as much as digits as its factorization.
141202244402243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 98304, while the sum is 35.
Adding to 141202244402243 its reverse (342204442202141), we get a palindrome (483406686604384).
The spelling of 141202244402243 in words is "one hundred forty-one trillion, two hundred two billion, two hundred forty-four million, four hundred two thousand, two hundred forty-three".
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