Base | Representation |
---|---|
bin | 11010010011010001… |
… | …01110010011111111 |
3 | 1100110001212021111201 |
4 | 31021220232103333 |
5 | 212404300022421 |
6 | 10253051200331 |
7 | 1006625455351 |
oct | 151150562377 |
9 | 40401767451 |
10 | 14120314111 |
11 | 5a96604a92 |
12 | 28a0a460a7 |
13 | 1440515a67 |
14 | 97d4750d1 |
15 | 57999bb91 |
hex | 349a2e4ff |
14120314111 has 2 divisors, whose sum is σ = 14120314112. Its totient is φ = 14120314110.
The previous prime is 14120314097. The next prime is 14120314139. The reversal of 14120314111 is 11141302141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14120314111 - 217 = 14120183039 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14120314211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7060157055 + 7060157056.
It is an arithmetic number, because the mean of its divisors is an integer number (7060157056).
Almost surely, 214120314111 is an apocalyptic number.
14120314111 is a deficient number, since it is larger than the sum of its proper divisors (1).
14120314111 is an equidigital number, since it uses as much as digits as its factorization.
14120314111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 14120314111 its reverse (11141302141), we get a palindrome (25261616252).
The spelling of 14120314111 in words is "fourteen billion, one hundred twenty million, three hundred fourteen thousand, one hundred eleven".
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