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141203323314341 is a prime number
BaseRepresentation
bin100000000110110001110101…
…111011010110000010100101
3200111221220110101100111210222
4200012301311323112002211
5122001433401232024331
61220151524453454125
741512413661506161
oct4006616573260245
9614856411314728
10141203323314341
1140a9aaa1936612
1213a06197341345
1360a35546815a2
1426c23c4d3dca1
15114d050d32b7b
hex806c75ed60a5

141203323314341 has 2 divisors, whose sum is σ = 141203323314342. Its totient is φ = 141203323314340.

The previous prime is 141203323314241. The next prime is 141203323314349. The reversal of 141203323314341 is 143413323302141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 138873945301441 + 2329378012900 = 11784479^2 + 1526230^2 .

It is a cyclic number.

It is not a de Polignac number, because 141203323314341 - 214 = 141203323297957 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141203323314349) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70601661657170 + 70601661657171.

It is an arithmetic number, because the mean of its divisors is an integer number (70601661657171).

Almost surely, 2141203323314341 is an apocalyptic number.

It is an amenable number.

141203323314341 is a deficient number, since it is larger than the sum of its proper divisors (1).

141203323314341 is an equidigital number, since it uses as much as digits as its factorization.

141203323314341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 62208, while the sum is 35.

Adding to 141203323314341 its reverse (143413323302141), we get a palindrome (284616646616482).

The spelling of 141203323314341 in words is "one hundred forty-one trillion, two hundred three billion, three hundred twenty-three million, three hundred fourteen thousand, three hundred forty-one".