Base | Representation |
---|---|
bin | 10100100011000100001… |
… | …110001011010011011111 |
3 | 11222222201120212102100022 |
4 | 110203010032023103133 |
5 | 141113330034324433 |
6 | 3000403254022355 |
7 | 204005462134121 |
oct | 24430416132337 |
9 | 4888646772308 |
10 | 1412041323743 |
11 | 4a4930574016 |
12 | 1a97b59479bb |
13 | a32024a98cb |
14 | 4c4b3903211 |
15 | 26ae5344698 |
hex | 148c438b4df |
1412041323743 has 2 divisors, whose sum is σ = 1412041323744. Its totient is φ = 1412041323742.
The previous prime is 1412041323709. The next prime is 1412041323757. The reversal of 1412041323743 is 3473231402141.
It is a strong prime.
It is an emirp because it is prime and its reverse (3473231402141) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1412041323743 - 216 = 1412041258207 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1412041323773) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706020661871 + 706020661872.
It is an arithmetic number, because the mean of its divisors is an integer number (706020661872).
Almost surely, 21412041323743 is an apocalyptic number.
1412041323743 is a deficient number, since it is larger than the sum of its proper divisors (1).
1412041323743 is an equidigital number, since it uses as much as digits as its factorization.
1412041323743 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48384, while the sum is 35.
Adding to 1412041323743 its reverse (3473231402141), we get a palindrome (4885272725884).
The spelling of 1412041323743 in words is "one trillion, four hundred twelve billion, forty-one million, three hundred twenty-three thousand, seven hundred forty-three".
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