Base | Representation |
---|---|
bin | 10100100011000100001… |
… | …110011110000001011011 |
3 | 11222222201121000022111212 |
4 | 110203010032132001123 |
5 | 141113330044303121 |
6 | 3000403255413335 |
7 | 204005462603465 |
oct | 24430416360133 |
9 | 4888647008455 |
10 | 1412041400411 |
11 | 4a4930616684 |
12 | 1a97b598424b |
13 | a3202505785 |
14 | 4c4b3923135 |
15 | 26ae535c25b |
hex | 148c439e05b |
1412041400411 has 2 divisors, whose sum is σ = 1412041400412. Its totient is φ = 1412041400410.
The previous prime is 1412041400389. The next prime is 1412041400509. The reversal of 1412041400411 is 1140041402141.
It is a weak prime.
It is an emirp because it is prime and its reverse (1140041402141) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1412041400411 - 238 = 1137163493467 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (1412041400111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706020700205 + 706020700206.
It is an arithmetic number, because the mean of its divisors is an integer number (706020700206).
Almost surely, 21412041400411 is an apocalyptic number.
1412041400411 is a deficient number, since it is larger than the sum of its proper divisors (1).
1412041400411 is an equidigital number, since it uses as much as digits as its factorization.
1412041400411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 512, while the sum is 23.
Adding to 1412041400411 its reverse (1140041402141), we get a palindrome (2552082802552).
The spelling of 1412041400411 in words is "one trillion, four hundred twelve billion, forty-one million, four hundred thousand, four hundred eleven".
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