14120854372693 has 2 divisors, whose sum is σ = 14120854372694. Its totient is φ = 14120854372692.

The previous prime is 14120854372649. The next prime is 14120854372733. The reversal of 14120854372693 is 39627345802141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12441012861124 + 1679841511569 = 3527182^2 + 1296087^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14120854372693 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14120854312693) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7060427186346 + 7060427186347.

It is an arithmetic number, because the mean of its divisors is an integer number (7060427186347).

It is a 1-persistent number, because it is pandigital, but 2⋅14120854372693 = 28241708745386 is not.

Almost surely, 2^{14120854372693} is an apocalyptic number.

It is an amenable number.

14120854372693 is a deficient number, since it is larger than the sum of its proper divisors (1).

14120854372693 is an equidigital number, since it uses as much as digits as its factorization.

14120854372693 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8709120, while the sum is 55.

The spelling of 14120854372693 in words is "fourteen trillion, one hundred twenty billion, eight hundred fifty-four million, three hundred seventy-two thousand, six hundred ninety-three".