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141211022043341 is a prime number
BaseRepresentation
bin100000000110111001000000…
…110011101010100011001101
3200111222122022220212110121002
4200012321000303222203031
5122002100133120341331
61220155240432150045
741513105523564215
oct4006710063524315
9614878286773532
10141211022043341
1140aa3292641668
1213a07785698325
1360a41b0670233
1426c29155c3245
15114d351b6c9cb
hex806e40cea8cd

141211022043341 has 2 divisors, whose sum is σ = 141211022043342. Its totient is φ = 141211022043340.

The previous prime is 141211022043319. The next prime is 141211022043383. The reversal of 141211022043341 is 143340220112141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 111821721027241 + 29389301016100 = 10574579^2 + 5421190^2 .

It is a cyclic number.

It is not a de Polignac number, because 141211022043341 - 222 = 141211017849037 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141211022045341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70605511021670 + 70605511021671.

It is an arithmetic number, because the mean of its divisors is an integer number (70605511021671).

Almost surely, 2141211022043341 is an apocalyptic number.

It is an amenable number.

141211022043341 is a deficient number, since it is larger than the sum of its proper divisors (1).

141211022043341 is an equidigital number, since it uses as much as digits as its factorization.

141211022043341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 141211022043341 its reverse (143340220112141), we get a palindrome (284551242155482).

The spelling of 141211022043341 in words is "one hundred forty-one trillion, two hundred eleven billion, twenty-two million, forty-three thousand, three hundred forty-one".