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14121114131 is a prime number
BaseRepresentation
bin11010010011010111…
…10001101000010011
31100110010100220221002
431021223301220103
5212410001123011
610253120252215
71006635326645
oct151153615023
940403326832
1014121114131
115a97001063
1228a117106b
131440735c47
1497d602895
15579aa8c3b
hex349af1a13

14121114131 has 2 divisors, whose sum is σ = 14121114132. Its totient is φ = 14121114130.

The previous prime is 14121114061. The next prime is 14121114143. The reversal of 14121114131 is 13141112141.

14121114131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14121114131 is a prime.

It is a super-2 number, since 2×141211141312 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14121114151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7060557065 + 7060557066.

It is an arithmetic number, because the mean of its divisors is an integer number (7060557066).

Almost surely, 214121114131 is an apocalyptic number.

14121114131 is a deficient number, since it is larger than the sum of its proper divisors (1).

14121114131 is an equidigital number, since it uses as much as digits as its factorization.

14121114131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 96, while the sum is 20.

Adding to 14121114131 its reverse (13141112141), we get a palindrome (27262226272).

The spelling of 14121114131 in words is "fourteen billion, one hundred twenty-one million, one hundred fourteen thousand, one hundred thirty-one".