14121134437 has 4 divisors (see below), whose sum is σ = 14121993600. Its totient is φ = 14120275276.

The previous prime is 14121134413. The next prime is 14121134449. The reversal of 14121134437 is 73443112141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14121134437 - 2⁷ = 14121134309 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14121134399 and 14121134408.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14121132437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 404437 + ... + 437962.

It is an arithmetic number, because the mean of its divisors is an integer number (3530498400).

Almost surely, 2^14121134437 is an apocalyptic number.

It is an amenable number.

14121134437 is a deficient number, since it is larger than the sum of its proper divisors (859163).

14121134437 is an equidigital number, since it uses as much as digits as its factorization.

14121134437 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 859162.

The product of its digits is 8064, while the sum is 31.

Adding to 14121134437 its reverse (73443112141), we get a palindrome (87564246578).

The spelling of 14121134437 in words is "fourteen billion, one hundred twenty-one million, one hundred thirty-four thousand, four hundred thirty-seven".