Base | Representation |
---|---|
bin | 10100100011001000101… |
… | …000001100100100001111 |
3 | 11222222220201222102221011 |
4 | 110203020220030210033 |
5 | 141114003001103034 |
6 | 3000414454350051 |
7 | 204010350415615 |
oct | 24431050144417 |
9 | 4888821872834 |
10 | 1412115253519 |
11 | 4a4969279603 |
12 | 1a981665b327 |
13 | a32148c3039 |
14 | 4c4bd6696b5 |
15 | 26aeba99864 |
hex | 148c8a0c90f |
1412115253519 has 2 divisors, whose sum is σ = 1412115253520. Its totient is φ = 1412115253518.
The previous prime is 1412115253513. The next prime is 1412115253541. The reversal of 1412115253519 is 9153525112141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1412115253519 - 211 = 1412115251471 is a prime.
It is a super-2 number, since 2×14121152535192 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1412115253513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706057626759 + 706057626760.
It is an arithmetic number, because the mean of its divisors is an integer number (706057626760).
Almost surely, 21412115253519 is an apocalyptic number.
1412115253519 is a deficient number, since it is larger than the sum of its proper divisors (1).
1412115253519 is an equidigital number, since it uses as much as digits as its factorization.
1412115253519 is an evil number, because the sum of its binary digits is even.
The product of its digits is 54000, while the sum is 40.
The spelling of 1412115253519 in words is "one trillion, four hundred twelve billion, one hundred fifteen million, two hundred fifty-three thousand, five hundred nineteen".
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