Base | Representation |
---|---|
bin | 100000000110111001111101… |
… | …011111010101000000100111 |
3 | 200111222201221212120020112011 |
4 | 200012321331133111000213 |
5 | 122002104224232404112 |
6 | 1220155525441135051 |
7 | 41513142665243602 |
oct | 4006717537250047 |
9 | 614881855506464 |
10 | 141212040122407 |
11 | 40aa3765293521 |
12 | 13a07a0a62a487 |
13 | 60a431356a397 |
14 | 26c29b08b9339 |
15 | 114d3b1220aa7 |
hex | 806e7d7d5027 |
141212040122407 has 2 divisors, whose sum is σ = 141212040122408. Its totient is φ = 141212040122406.
The previous prime is 141212040122389. The next prime is 141212040122443. The reversal of 141212040122407 is 704221040212141.
141212040122407 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 141212040122407 - 215 = 141212040089639 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (141212940122407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70606020061203 + 70606020061204.
It is an arithmetic number, because the mean of its divisors is an integer number (70606020061204).
Almost surely, 2141212040122407 is an apocalyptic number.
141212040122407 is a deficient number, since it is larger than the sum of its proper divisors (1).
141212040122407 is an equidigital number, since it uses as much as digits as its factorization.
141212040122407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7168, while the sum is 31.
Adding to 141212040122407 its reverse (704221040212141), we get a palindrome (845433080334548).
The spelling of 141212040122407 in words is "one hundred forty-one trillion, two hundred twelve billion, forty million, one hundred twenty-two thousand, four hundred seven".
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