Base | Representation |
---|---|
bin | 100000000110111010110110… |
… | …110101111010001100110111 |
3 | 200111222211102221011010100011 |
4 | 200012322312311322030313 |
5 | 122002113212044440343 |
6 | 1220200205133001051 |
7 | 41513205561056236 |
oct | 4006726665721467 |
9 | 614884387133304 |
10 | 141213002343223 |
11 | 40aa4109453238 |
12 | 13a08038923187 |
13 | 60a4437a0a805 |
14 | 26c2a625d0b1d |
15 | 114d41a93d29d |
hex | 806eb6d7a337 |
141213002343223 has 2 divisors, whose sum is σ = 141213002343224. Its totient is φ = 141213002343222.
The previous prime is 141213002343163. The next prime is 141213002343229. The reversal of 141213002343223 is 322343200312141.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-141213002343223 is a prime.
It is a super-2 number, since 2×1412130023432232 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (141213002343229) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70606501171611 + 70606501171612.
It is an arithmetic number, because the mean of its divisors is an integer number (70606501171612).
Almost surely, 2141213002343223 is an apocalyptic number.
141213002343223 is a deficient number, since it is larger than the sum of its proper divisors (1).
141213002343223 is an equidigital number, since it uses as much as digits as its factorization.
141213002343223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 141213002343223 its reverse (322343200312141), we get a palindrome (463556202655364).
The spelling of 141213002343223 in words is "one hundred forty-one trillion, two hundred thirteen billion, two million, three hundred forty-three thousand, two hundred twenty-three".
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