14121312403111 has 2 divisors, whose sum is σ = 14121312403112. Its totient is φ = 14121312403110.

The previous prime is 14121312403021. The next prime is 14121312403123. The reversal of 14121312403111 is 11130421312141.

It is a strong prime.

It is an emirp because it is prime and its reverse (11130421312141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14121312403111 - 2¹⁵ = 14121312370343 is a prime.

It is a super-2 number, since 2×14121312403111² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14121312406111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7060656201555 + 7060656201556.

It is an arithmetic number, because the mean of its divisors is an integer number (7060656201556).

Almost surely, 2^{14121312403111} is an apocalyptic number.

14121312403111 is a deficient number, since it is larger than the sum of its proper divisors (1).

14121312403111 is an equidigital number, since it uses as much as digits as its factorization.

14121312403111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 14121312403111 its reverse (11130421312141), we get a palindrome (25251733715252).

The spelling of 14121312403111 in words is "fourteen trillion, one hundred twenty-one billion, three hundred twelve million, four hundred three thousand, one hundred eleven".