1412131453457 has 2 divisors, whose sum is σ = 1412131453458. Its totient is φ = 1412131453456.

The previous prime is 1412131453451. The next prime is 1412131453459. The reversal of 1412131453457 is 7543541312141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1256587192576 + 155544260881 = 1120976^2 + 394391^2 .

It is an emirp because it is prime and its reverse (7543541312141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1412131453457 - 2¹⁶ = 1412131387921 is a prime.

It is a super-4 number, since 4×1412131453457⁴ (a number of 50 digits) contains 4444 as substring.

Together with 1412131453459, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1412131453451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706065726728 + 706065726729.

It is an arithmetic number, because the mean of its divisors is an integer number (706065726729).

Almost surely, 2^{1412131453457} is an apocalyptic number.

It is an amenable number.

1412131453457 is a deficient number, since it is larger than the sum of its proper divisors (1).

1412131453457 is an equidigital number, since it uses as much as digits as its factorization.

1412131453457 is an evil number, because the sum of its binary digits is even.

The product of its digits is 201600, while the sum is 41.

Adding to 1412131453457 its reverse (7543541312141), we get a palindrome (8955672765598).

The spelling of 1412131453457 in words is "one trillion, four hundred twelve billion, one hundred thirty-one million, four hundred fifty-three thousand, four hundred fifty-seven".