141213402303133 has 4 divisors (see below), whose sum is σ = 141213510984348. Its totient is φ = 141213293621920.

The previous prime is 141213402303131. The next prime is 141213402303137. The reversal of 141213402303133 is 331303204312141.

141213402303133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 49033087583769 + 92180314719364 = 7002363^2 + 9601058^2 .

It is a cyclic number.

It is not a de Polignac number, because 141213402303133 - 2¹ = 141213402303131 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 141213402303095 and 141213402303104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141213402303131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52367728 + ... + 54998233.

It is an arithmetic number, because the mean of its divisors is an integer number (35303377746087).

Almost surely, 2^{141213402303133} is an apocalyptic number.

It is an amenable number.

141213402303133 is a deficient number, since it is larger than the sum of its proper divisors (108681215).

141213402303133 is a wasteful number, since it uses less digits than its factorization.

141213402303133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 108681214.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 141213402303133 its reverse (331303204312141), we get a palindrome (472516606615274).

The spelling of 141213402303133 in words is "one hundred forty-one trillion, two hundred thirteen billion, four hundred two million, three hundred three thousand, one hundred thirty-three".