141214204433111 has 4 divisors (see below), whose sum is σ = 141214868892432. Its totient is φ = 141213539973792.

The previous prime is 141214204433069. The next prime is 141214204433123. The reversal of 141214204433111 is 111334402412141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-141214204433111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141214204433131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 331910771 + ... + 332335956.

It is an arithmetic number, because the mean of its divisors is an integer number (35303717223108).

Almost surely, 2^{141214204433111} is an apocalyptic number.

141214204433111 is a deficient number, since it is larger than the sum of its proper divisors (664459321).

141214204433111 is an equidigital number, since it uses as much as digits as its factorization.

141214204433111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 664459320.

The product of its (nonzero) digits is 9216, while the sum is 32.

Adding to 141214204433111 its reverse (111334402412141), we get a palindrome (252548606845252).

The spelling of 141214204433111 in words is "one hundred forty-one trillion, two hundred fourteen billion, two hundred four million, four hundred thirty-three thousand, one hundred eleven".