1412201421133 has 4 divisors (see below), whose sum is σ = 1412203818688. Its totient is φ = 1412199023580.

The previous prime is 1412201421119. The next prime is 1412201421167. The reversal of 1412201421133 is 3311241022141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 1412201421133 - 2²¹ = 1412199323981 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1412201421098 and 1412201421107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1412201421173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 362860 + ... + 1719322.

It is an arithmetic number, because the mean of its divisors is an integer number (353050954672).

Almost surely, 2^{1412201421133} is an apocalyptic number.

It is an amenable number.

1412201421133 is a deficient number, since it is larger than the sum of its proper divisors (2397555).

1412201421133 is a wasteful number, since it uses less digits than its factorization.

1412201421133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2397554.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1412201421133 its reverse (3311241022141), we get a palindrome (4723442443274).

The spelling of 1412201421133 in words is "one trillion, four hundred twelve billion, two hundred one million, four hundred twenty-one thousand, one hundred thirty-three".