Base | Representation |
---|---|
bin | 11010010011011110… |
… | …10001100101101111 |
3 | 1100110012002112021122 |
4 | 31021233101211233 |
5 | 212410220001341 |
6 | 10253152051155 |
7 | 1006646200262 |
oct | 151157214557 |
9 | 40405075248 |
10 | 14122031471 |
11 | 5a97578299 |
12 | 28a1533abb |
13 | 1440997652 |
14 | 97d7a0cd9 |
15 | 579bda94b |
hex | 349bd196f |
14122031471 has 2 divisors, whose sum is σ = 14122031472. Its totient is φ = 14122031470.
The previous prime is 14122031423. The next prime is 14122031501. The reversal of 14122031471 is 17413022141.
It is a strong prime.
It is an emirp because it is prime and its reverse (17413022141) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14122031471 is a prime.
It is a super-3 number, since 3×141220314713 (a number of 31 digits) contains 333 as substring.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 14122031471.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14122031401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7061015735 + 7061015736.
It is an arithmetic number, because the mean of its divisors is an integer number (7061015736).
Almost surely, 214122031471 is an apocalyptic number.
14122031471 is a deficient number, since it is larger than the sum of its proper divisors (1).
14122031471 is an equidigital number, since it uses as much as digits as its factorization.
14122031471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 26.
The spelling of 14122031471 in words is "fourteen billion, one hundred twenty-two million, thirty-one thousand, four hundred seventy-one".
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