Base | Representation |
---|---|
bin | 10100100011001101110… |
… | …111110001101110001011 |
3 | 12000000010212111210200011 |
4 | 110203031313301232023 |
5 | 141114143011131242 |
6 | 3000431320052351 |
7 | 204012466226305 |
oct | 24431567615613 |
9 | 5000125453604 |
10 | 1412203223947 |
11 | 4a4a039a403a |
12 | 1a98400040b7 |
13 | a3229bb4249 |
14 | 4c4cb208975 |
15 | 26b04674d17 |
hex | 148cddf1b8b |
1412203223947 has 2 divisors, whose sum is σ = 1412203223948. Its totient is φ = 1412203223946.
The previous prime is 1412203223929. The next prime is 1412203223957. The reversal of 1412203223947 is 7493223022141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1412203223947 - 231 = 1410055740299 is a prime.
It is not a weakly prime, because it can be changed into another prime (1412203223927) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706101611973 + 706101611974.
It is an arithmetic number, because the mean of its divisors is an integer number (706101611974).
Almost surely, 21412203223947 is an apocalyptic number.
1412203223947 is a deficient number, since it is larger than the sum of its proper divisors (1).
1412203223947 is an equidigital number, since it uses as much as digits as its factorization.
1412203223947 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 145152, while the sum is 40.
The spelling of 1412203223947 in words is "one trillion, four hundred twelve billion, two hundred three million, two hundred twenty-three thousand, nine hundred forty-seven".
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