141220557113 has 2 divisors, whose sum is σ = 141220557114. Its totient is φ = 141220557112.

The previous prime is 141220557077. The next prime is 141220557167. The reversal of 141220557113 is 311755022141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 137638774009 + 3581783104 = 370997^2 + 59848^2 .

It is an emirp because it is prime and its reverse (311755022141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 141220557113 - 2⁸ = 141220556857 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 141220557113.

It is not a weakly prime, because it can be changed into another prime (141220557913) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70610278556 + 70610278557.

It is an arithmetic number, because the mean of its divisors is an integer number (70610278557).

Almost surely, 2^141220557113 is an apocalyptic number.

It is an amenable number.

141220557113 is a deficient number, since it is larger than the sum of its proper divisors (1).

141220557113 is an equidigital number, since it uses as much as digits as its factorization.

141220557113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8400, while the sum is 32.

Adding to 141220557113 its reverse (311755022141), we get a palindrome (452975579254).

The spelling of 141220557113 in words is "one hundred forty-one billion, two hundred twenty million, five hundred fifty-seven thousand, one hundred thirteen".