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141221142113 is a prime number
BaseRepresentation
bin1000001110000101101…
…1111001111001100001
3111111111221111022210212
42003201123321321201
54303210103021423
6144513123103505
713126406621252
oct2034133717141
9444457438725
10141221142113
11549897202a7
1223452811b95
13104178796ac
146b998a2b29
153a18036578
hex20e16f9e61

141221142113 has 2 divisors, whose sum is σ = 141221142114. Its totient is φ = 141221142112.

The previous prime is 141221142079. The next prime is 141221142121. The reversal of 141221142113 is 311241122141.

141221142113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 72696562129 + 68524579984 = 269623^2 + 261772^2 .

It is a cyclic number.

It is not a de Polignac number, because 141221142113 - 220 = 141220093537 is a prime.

It is not a weakly prime, because it can be changed into another prime (141221142613) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70610571056 + 70610571057.

It is an arithmetic number, because the mean of its divisors is an integer number (70610571057).

Almost surely, 2141221142113 is an apocalyptic number.

It is an amenable number.

141221142113 is a deficient number, since it is larger than the sum of its proper divisors (1).

141221142113 is an equidigital number, since it uses as much as digits as its factorization.

141221142113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 384, while the sum is 23.

Adding to 141221142113 its reverse (311241122141), we get a palindrome (452462264254).

The spelling of 141221142113 in words is "one hundred forty-one billion, two hundred twenty-one million, one hundred forty-two thousand, one hundred thirteen".