Base | Representation |
---|---|
bin | 10100100011001110100… |
… | …000111101100101001111 |
3 | 12000000011121211022122221 |
4 | 110203032200331211033 |
5 | 141114203242123211 |
6 | 3000432343320211 |
7 | 204012660054034 |
oct | 24431640754517 |
9 | 5000147738587 |
10 | 1412214020431 |
11 | 4a4a09aa8655 |
12 | 1a9843750067 |
13 | a322c1c44b6 |
14 | 4c4cc81938b |
15 | 26b055a8c71 |
hex | 148ce83d94f |
1412214020431 has 2 divisors, whose sum is σ = 1412214020432. Its totient is φ = 1412214020430.
The previous prime is 1412214020353. The next prime is 1412214020447. The reversal of 1412214020431 is 1340204122141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1412214020431 - 213 = 1412214012239 is a prime.
It is a super-2 number, since 2×14122140204312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1412214020396 and 1412214020405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1412214020491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706107010215 + 706107010216.
It is an arithmetic number, because the mean of its divisors is an integer number (706107010216).
Almost surely, 21412214020431 is an apocalyptic number.
1412214020431 is a deficient number, since it is larger than the sum of its proper divisors (1).
1412214020431 is an equidigital number, since it uses as much as digits as its factorization.
1412214020431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 1412214020431 its reverse (1340204122141), we get a palindrome (2752418142572).
The spelling of 1412214020431 in words is "one trillion, four hundred twelve billion, two hundred fourteen million, twenty thousand, four hundred thirty-one".
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