Base | Representation |
---|---|
bin | 11010010011011111… |
… | …01100011010010011 |
3 | 1100110012022002222112 |
4 | 31021233230122103 |
5 | 212410232010311 |
6 | 10253154255535 |
7 | 1006650135464 |
oct | 151157543223 |
9 | 40405262875 |
10 | 14122141331 |
11 | 5a97642891 |
12 | 28a15875ab |
13 | 1440a0565c |
14 | 97d7ccd6b |
15 | 579c0d28b |
hex | 349bec693 |
14122141331 has 2 divisors, whose sum is σ = 14122141332. Its totient is φ = 14122141330.
The previous prime is 14122141279. The next prime is 14122141379. The reversal of 14122141331 is 13314122141.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14122141331 is a prime.
It is a super-2 number, since 2×141221413312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14122141297 and 14122141306.
It is not a weakly prime, because it can be changed into another prime (14122141391) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7061070665 + 7061070666.
It is an arithmetic number, because the mean of its divisors is an integer number (7061070666).
Almost surely, 214122141331 is an apocalyptic number.
14122141331 is a deficient number, since it is larger than the sum of its proper divisors (1).
14122141331 is an equidigital number, since it uses as much as digits as its factorization.
14122141331 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 576, while the sum is 23.
Adding to 14122141331 its reverse (13314122141), we get a palindrome (27436263472).
The spelling of 14122141331 in words is "fourteen billion, one hundred twenty-two million, one hundred forty-one thousand, three hundred thirty-one".
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