Base | Representation |
---|---|
bin | 10100100011001110111… |
… | …000100111101011000111 |
3 | 12000000012001111101211021 |
4 | 110203032320213223013 |
5 | 141114211334102101 |
6 | 3000433124252011 |
7 | 204013063553614 |
oct | 24431670475307 |
9 | 5000161441737 |
10 | 1412220222151 |
11 | 4a4a12554042 |
12 | 1a9845841007 |
13 | a323058625b |
14 | 4c4cd59150b |
15 | 26b05dd15a1 |
hex | 148cee27ac7 |
1412220222151 has 2 divisors, whose sum is σ = 1412220222152. Its totient is φ = 1412220222150.
The previous prime is 1412220222031. The next prime is 1412220222197. The reversal of 1412220222151 is 1512220222141.
It is a strong prime.
It is an emirp because it is prime and its reverse (1512220222141) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1412220222151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1412220222251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706110111075 + 706110111076.
It is an arithmetic number, because the mean of its divisors is an integer number (706110111076).
Almost surely, 21412220222151 is an apocalyptic number.
1412220222151 is a deficient number, since it is larger than the sum of its proper divisors (1).
1412220222151 is an equidigital number, since it uses as much as digits as its factorization.
1412220222151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1280, while the sum is 25.
Adding to 1412220222151 its reverse (1512220222141), we get a palindrome (2924440444292).
The spelling of 1412220222151 in words is "one trillion, four hundred twelve billion, two hundred twenty million, two hundred twenty-two thousand, one hundred fifty-one".
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