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1412222401355 = 51671691284313
BaseRepresentation
bin10100100011001111000…
…000111011101101001011
312000000012012121010010112
4110203033000323231023
5141114212413320410
63000433243104535
7204013121231153
oct24431700735513
95000165533115
101412222401355
114a4a13802337
121a984651214b
13a3230b6a11c
144c4cd99b763
1526b061b2105
hex148cf03bb4b

1412222401355 has 8 divisors (see below), whose sum is σ = 1704814588512. Its totient is φ = 1123012783168.

The previous prime is 1412222401301. The next prime is 1412222401417. The reversal of 1412222401355 is 5531042222141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1412222401355 is a prime.

It is a super-2 number, since 2×14122224013552 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 845641322 + ... + 845642991.

It is an arithmetic number, because the mean of its divisors is an integer number (213101823564).

Almost surely, 21412222401355 is an apocalyptic number.

1412222401355 is a deficient number, since it is larger than the sum of its proper divisors (292592187157).

1412222401355 is a wasteful number, since it uses less digits than its factorization.

1412222401355 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1691284485.

The product of its (nonzero) digits is 19200, while the sum is 32.

Adding to 1412222401355 its reverse (5531042222141), we get a palindrome (6943264623496).

The spelling of 1412222401355 in words is "one trillion, four hundred twelve billion, two hundred twenty-two million, four hundred one thousand, three hundred fifty-five".

Divisors: 1 5 167 835 1691284313 8456421565 282444480271 1412222401355