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141222242003 = 144239791461
BaseRepresentation
bin1000001110000110000…
…0000110011011010011
3111111112000120012120112
42003201200012123103
54303210343221003
6144513202431535
713126422152033
oct2034140063323
9444460505515
10141222242003
115498a3016a7
12234530625ab
1310417b7320b
146b99aab8c3
153a181a23d8
hex20e18066d3

141222242003 has 4 divisors (see below), whose sum is σ = 141232047888. Its totient is φ = 141212436120.

The previous prime is 141222241997. The next prime is 141222242047. The reversal of 141222242003 is 300242222141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 141222242003 - 218 = 141221979859 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 141222242003.

It is not an unprimeable number, because it can be changed into a prime (141222242503) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4881308 + ... + 4910153.

It is an arithmetic number, because the mean of its divisors is an integer number (35308011972).

Almost surely, 2141222242003 is an apocalyptic number.

141222242003 is a deficient number, since it is larger than the sum of its proper divisors (9805885).

141222242003 is an equidigital number, since it uses as much as digits as its factorization.

141222242003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9805884.

The product of its (nonzero) digits is 1536, while the sum is 23.

Adding to 141222242003 its reverse (300242222141), we get a palindrome (441464464144).

The spelling of 141222242003 in words is "one hundred forty-one billion, two hundred twenty-two million, two hundred forty-two thousand, three".

Divisors: 1 14423 9791461 141222242003