Base | Representation |
---|---|
bin | 1000001110000110000… |
… | …0000110011011010011 |
3 | 111111112000120012120112 |
4 | 2003201200012123103 |
5 | 4303210343221003 |
6 | 144513202431535 |
7 | 13126422152033 |
oct | 2034140063323 |
9 | 444460505515 |
10 | 141222242003 |
11 | 5498a3016a7 |
12 | 234530625ab |
13 | 10417b7320b |
14 | 6b99aab8c3 |
15 | 3a181a23d8 |
hex | 20e18066d3 |
141222242003 has 4 divisors (see below), whose sum is σ = 141232047888. Its totient is φ = 141212436120.
The previous prime is 141222241997. The next prime is 141222242047. The reversal of 141222242003 is 300242222141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 141222242003 - 218 = 141221979859 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 141222242003.
It is not an unprimeable number, because it can be changed into a prime (141222242503) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4881308 + ... + 4910153.
It is an arithmetic number, because the mean of its divisors is an integer number (35308011972).
Almost surely, 2141222242003 is an apocalyptic number.
141222242003 is a deficient number, since it is larger than the sum of its proper divisors (9805885).
141222242003 is an equidigital number, since it uses as much as digits as its factorization.
141222242003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9805884.
The product of its (nonzero) digits is 1536, while the sum is 23.
Adding to 141222242003 its reverse (300242222141), we get a palindrome (441464464144).
The spelling of 141222242003 in words is "one hundred forty-one billion, two hundred twenty-two million, two hundred forty-two thousand, three".
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