Base | Representation |
---|---|
bin | 11010010011100000… |
… | …00101010110110011 |
3 | 1100110012111022010211 |
4 | 31021300011112303 |
5 | 212410243243012 |
6 | 10253200404551 |
7 | 1006651042411 |
oct | 151160052663 |
9 | 40405438124 |
10 | 14122243507 |
11 | 5a97702629 |
12 | 28a1616757 |
13 | 1440a40008 |
14 | 97d8182b1 |
15 | 579c2d6a7 |
hex | 349c055b3 |
14122243507 has 2 divisors, whose sum is σ = 14122243508. Its totient is φ = 14122243506.
The previous prime is 14122243489. The next prime is 14122243511. The reversal of 14122243507 is 70534222141.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (70534222141) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14122243507 is a prime.
It is not a weakly prime, because it can be changed into another prime (14122243517) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7061121753 + 7061121754.
It is an arithmetic number, because the mean of its divisors is an integer number (7061121754).
Almost surely, 214122243507 is an apocalyptic number.
14122243507 is a deficient number, since it is larger than the sum of its proper divisors (1).
14122243507 is an equidigital number, since it uses as much as digits as its factorization.
14122243507 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13440, while the sum is 31.
Adding to 14122243507 its reverse (70534222141), we get a palindrome (84656465648).
The spelling of 14122243507 in words is "fourteen billion, one hundred twenty-two million, two hundred forty-three thousand, five hundred seven".
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