Base | Representation |
---|---|
bin | 100000000111000100010010… |
… | …011111111100100001101100 |
3 | 200112000210120202011121121211 |
4 | 200013010102133330201230 |
5 | 122002244432241232134 |
6 | 1220205002120204204 |
7 | 41514014545662415 |
oct | 4007042237744154 |
9 | 615023522147554 |
10 | 141223130024044 |
11 | 40aa8436245792 |
12 | 13a09ba4609664 |
13 | 60a538ccb0c63 |
14 | 26c33436ac80c |
15 | 114d80eb1c764 |
hex | 8071127fc86c |
141223130024044 has 24 divisors (see below), whose sum is σ = 249546289644288. Its totient is φ = 69924225235920.
The previous prime is 141223130024017. The next prime is 141223130024089. The reversal of 141223130024044 is 440420031322141.
It is a happy number.
It is a super-2 number, since 2×1412231300240442 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 141223130023997 and 141223130024015.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11792409 + ... + 20530639.
It is an arithmetic number, because the mean of its divisors is an integer number (10397762068512).
Almost surely, 2141223130024044 is an apocalyptic number.
It is an amenable number.
141223130024044 is a deficient number, since it is larger than the sum of its proper divisors (108323159620244).
141223130024044 is a wasteful number, since it uses less digits than its factorization.
141223130024044 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8777565 (or 8777563 counting only the distinct ones).
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 141223130024044 its reverse (440420031322141), we get a palindrome (581643161346185).
The spelling of 141223130024044 in words is "one hundred forty-one trillion, two hundred twenty-three billion, one hundred thirty million, twenty-four thousand, forty-four".
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