14122400993 has 2 divisors, whose sum is σ = 14122400994. Its totient is φ = 14122400992.

The previous prime is 14122400983. The next prime is 14122401001. The reversal of 14122400993 is 39900422141.

14122400993 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12865911184 + 1256489809 = 113428^2 + 35447^2 .

It is a cyclic number.

It is not a de Polignac number, because 14122400993 - 2⁴ = 14122400977 is a prime.

It is not a weakly prime, because it can be changed into another prime (14122400953) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7061200496 + 7061200497.

It is an arithmetic number, because the mean of its divisors is an integer number (7061200497).

Almost surely, 2^14122400993 is an apocalyptic number.

It is an amenable number.

14122400993 is a deficient number, since it is larger than the sum of its proper divisors (1).

14122400993 is an equidigital number, since it uses as much as digits as its factorization.

14122400993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552, while the sum is 35.

The spelling of 14122400993 in words is "fourteen billion, one hundred twenty-two million, four hundred thousand, nine hundred ninety-three".