Base | Representation |
---|---|
bin | 100000000111000101001110… |
… | …111000100111101000101011 |
3 | 200112000220012100111110220202 |
4 | 200013011032320213220223 |
5 | 122002304021120000120 |
6 | 1220205250430342415 |
7 | 41514051630126545 |
oct | 4007051670475053 |
9 | 615026170443822 |
10 | 141224143125035 |
11 | 40aa89060a7533 |
12 | 13a0a22795aa0b |
13 | 60a54c1b572b9 |
14 | 26c33dc06a695 |
15 | 114d86da3a875 |
hex | 80714ee27a2b |
141224143125035 has 4 divisors (see below), whose sum is σ = 169468971750048. Its totient is φ = 112979314500024.
The previous prime is 141224143125017. The next prime is 141224143125077. The reversal of 141224143125035 is 530521341422141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 141224143125035 - 216 = 141224143059499 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 141224143125035.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14122414312499 + ... + 14122414312508.
It is an arithmetic number, because the mean of its divisors is an integer number (42367242937512).
Almost surely, 2141224143125035 is an apocalyptic number.
141224143125035 is a deficient number, since it is larger than the sum of its proper divisors (28244828625013).
141224143125035 is an equidigital number, since it uses as much as digits as its factorization.
141224143125035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28244828625012.
The product of its (nonzero) digits is 115200, while the sum is 38.
Adding to 141224143125035 its reverse (530521341422141), we get a palindrome (671745484547176).
The spelling of 141224143125035 in words is "one hundred forty-one trillion, two hundred twenty-four billion, one hundred forty-three million, one hundred twenty-five thousand, thirty-five".
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