Base | Representation |
---|---|
bin | 1000001110000111111… |
… | …0001100001111000001 |
3 | 111111112120101222000202 |
4 | 2003201332030033001 |
5 | 4303214403130423 |
6 | 144514043454545 |
7 | 13126546204322 |
oct | 2034176141701 |
9 | 444476358022 |
10 | 141230130113 |
11 | 549937aa0a6 |
12 | 23455827455 |
13 | 104196a5737 |
14 | 6b9ab62449 |
15 | 3a18c0e728 |
hex | 20e1f8c3c1 |
141230130113 has 2 divisors, whose sum is σ = 141230130114. Its totient is φ = 141230130112.
The previous prime is 141230130077. The next prime is 141230130191. The reversal of 141230130113 is 311031032141.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 127758349489 + 13471780624 = 357433^2 + 116068^2 .
It is a cyclic number.
It is not a de Polignac number, because 141230130113 - 28 = 141230129857 is a prime.
It is not a weakly prime, because it can be changed into another prime (141230130913) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70615065056 + 70615065057.
It is an arithmetic number, because the mean of its divisors is an integer number (70615065057).
Almost surely, 2141230130113 is an apocalyptic number.
It is an amenable number.
141230130113 is a deficient number, since it is larger than the sum of its proper divisors (1).
141230130113 is an equidigital number, since it uses as much as digits as its factorization.
141230130113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 141230130113 its reverse (311031032141), we get a palindrome (452261162254).
The spelling of 141230130113 in words is "one hundred forty-one billion, two hundred thirty million, one hundred thirty thousand, one hundred thirteen".
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