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1412302624169 is a prime number
BaseRepresentation
bin10100100011010011110…
…010111101010110101001
312000000101210112212010212
4110203103302331112221
5141114343432433134
63000445230350505
7204015114143003
oct24432362752651
95000353485125
101412302624169
114a4a55015988
121a986935b435
13a3244677a48
144c4da4c1373
1526b0d25bbce
hex148d3cbd5a9

1412302624169 has 2 divisors, whose sum is σ = 1412302624170. Its totient is φ = 1412302624168.

The previous prime is 1412302624079. The next prime is 1412302624171. The reversal of 1412302624169 is 9614262032141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 969594702400 + 442707921769 = 984680^2 + 665363^2 .

It is a cyclic number.

It is not a de Polignac number, because 1412302624169 - 220 = 1412301575593 is a prime.

It is a super-2 number, since 2×14123026241692 (a number of 25 digits) contains 22 as substring.

Together with 1412302624171, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1412302624969) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706151312084 + 706151312085.

It is an arithmetic number, because the mean of its divisors is an integer number (706151312085).

Almost surely, 21412302624169 is an apocalyptic number.

It is an amenable number.

1412302624169 is a deficient number, since it is larger than the sum of its proper divisors (1).

1412302624169 is an equidigital number, since it uses as much as digits as its factorization.

1412302624169 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 124416, while the sum is 41.

The spelling of 1412302624169 in words is "one trillion, four hundred twelve billion, three hundred two million, six hundred twenty-four thousand, one hundred sixty-nine".