Base | Representation |
---|---|
bin | 10100100011010100010… |
… | …011010101100110101111 |
3 | 12000000102101112002102002 |
4 | 110203110103111212233 |
5 | 141114403121041421 |
6 | 3000450132322515 |
7 | 204015246244124 |
oct | 24432423254657 |
9 | 5000371462362 |
10 | 1412311112111 |
11 | 4a4a59893009 |
12 | 1a987017343b |
13 | a324635a2b3 |
14 | 4c4db69074b |
15 | 26b0dd86b0b |
hex | 148d44d59af |
1412311112111 has 2 divisors, whose sum is σ = 1412311112112. Its totient is φ = 1412311112110.
The previous prime is 1412311112083. The next prime is 1412311112159. The reversal of 1412311112111 is 1112111132141.
It is a m-pointer prime, because the next prime (1412311112159) can be obtained adding 1412311112111 to its product of digits (48).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1412311112111 - 218 = 1412310849967 is a prime.
It is a super-2 number, since 2×14123111121112 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1412311112161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706155556055 + 706155556056.
It is an arithmetic number, because the mean of its divisors is an integer number (706155556056).
Almost surely, 21412311112111 is an apocalyptic number.
1412311112111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1412311112111 is an equidigital number, since it uses as much as digits as its factorization.
1412311112111 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 48, while the sum is 20.
Adding to 1412311112111 its reverse (1112111132141), we get a palindrome (2524422244252).
The spelling of 1412311112111 in words is "one trillion, four hundred twelve billion, three hundred eleven million, one hundred twelve thousand, one hundred eleven".
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