Base | Representation |
---|---|
bin | 1100110110000100101110… |
… | …0111110111101100010111 |
3 | 1212000011020121012120110012 |
4 | 3031201023213313230113 |
5 | 3322343123012242213 |
6 | 50012023341550435 |
7 | 2655235052365664 |
oct | 315411347675427 |
9 | 55004217176405 |
10 | 14123121212183 |
11 | 455564480a705 |
12 | 17011a487541b |
13 | 7b5a5c982419 |
14 | 36b7c4130a6b |
15 | 197594ddc4a8 |
hex | cd84b9f7b17 |
14123121212183 has 2 divisors, whose sum is σ = 14123121212184. Its totient is φ = 14123121212182.
The previous prime is 14123121212149. The next prime is 14123121212209. The reversal of 14123121212183 is 38121212132141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14123121212183 - 242 = 9725074701079 is a prime.
It is a super-2 number, since 2×141231212121832 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14123121212143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7061560606091 + 7061560606092.
It is an arithmetic number, because the mean of its divisors is an integer number (7061560606092).
Almost surely, 214123121212183 is an apocalyptic number.
14123121212183 is a deficient number, since it is larger than the sum of its proper divisors (1).
14123121212183 is an equidigital number, since it uses as much as digits as its factorization.
14123121212183 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4608, while the sum is 32.
The spelling of 14123121212183 in words is "fourteen trillion, one hundred twenty-three billion, one hundred twenty-one million, two hundred twelve thousand, one hundred eighty-three".
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