14123124340001 has 2 divisors, whose sum is σ = 14123124340002. Its totient is φ = 14123124340000.

The previous prime is 14123124339953. The next prime is 14123124340019. The reversal of 14123124340001 is 10004342132141.

14123124340001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8105841749776 + 6017282590225 = 2847076^2 + 2453015^2 .

It is a cyclic number.

It is not a de Polignac number, because 14123124340001 - 2¹⁰ = 14123124338977 is a prime.

It is a super-2 number, since 2×14123124340001² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14123124342001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7061562170000 + 7061562170001.

It is an arithmetic number, because the mean of its divisors is an integer number (7061562170001).

Almost surely, 2^{14123124340001} is an apocalyptic number.

It is an amenable number.

14123124340001 is a deficient number, since it is larger than the sum of its proper divisors (1).

14123124340001 is an equidigital number, since it uses as much as digits as its factorization.

14123124340001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 14123124340001 its reverse (10004342132141), we get a palindrome (24127466472142).

The spelling of 14123124340001 in words is "fourteen trillion, one hundred twenty-three billion, one hundred twenty-four million, three hundred forty thousand, one".