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14123124340000 = 255413179732941
BaseRepresentation
bin1100110110000100101111…
…0011110011010100100000
31212000011020211002111000021
43031201023303303110200
53322343124312340000
650012023533003224
72655235121103664
oct315411363632440
955004224074007
1014123124340000
114555646556685
1217011a5923514
137b5a60508cc0
1436b7c47068a4
1519759530911a
hexcd84bcf3520

14123124340000 has 480 divisors, whose sum is σ = 40028393701296. Its totient is φ = 4857200640000.

The previous prime is 14123124339953. The next prime is 14123124340001. The reversal of 14123124340000 is 4342132141.

It can be written as a sum of positive squares in 40 ways, for example, as 8880471520144 + 5242652819856 = 2980012^2 + 2289684^2 .

It is a super-2 number, since 2×141231243400002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (25).

It is not an unprimeable number, because it can be changed into a prime (14123124340001) by changing a digit.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 428723530 + ... + 428756470.

Almost surely, 214123124340000 is an apocalyptic number.

14123124340000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 14123124340000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20014196850648).

14123124340000 is an abundant number, since it is smaller than the sum of its proper divisors (25905269361296).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14123124340000 is a wasteful number, since it uses less digits than its factorization.

14123124340000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33098 (or 33075 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 14123124340000 its reverse (4342132141), we get a palindrome (14127466472141).

The spelling of 14123124340000 in words is "fourteen trillion, one hundred twenty-three billion, one hundred twenty-four million, three hundred forty thousand".