Base | Representation |
---|---|
bin | 10100100011010100111… |
… | …011001101111110100111 |
3 | 12000000110010012020022112 |
4 | 110203110323031332213 |
5 | 141114413310113011 |
6 | 3000451144351235 |
7 | 204015434145563 |
oct | 24432473157647 |
9 | 5000403166275 |
10 | 1412321566631 |
11 | 4a4a64783708 |
12 | 1a987377551b |
13 | a324857a9c1 |
14 | 4c4dcc126a3 |
15 | 26b0ec4e58b |
hex | 148d4ecdfa7 |
1412321566631 has 4 divisors (see below), whose sum is σ = 1415411986272. Its totient is φ = 1409231146992.
The previous prime is 1412321566571. The next prime is 1412321566651. The reversal of 1412321566631 is 1366651232141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1412321566631 - 210 = 1412321565607 is a prime.
It is a super-2 number, since 2×14123215666312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1412321566651) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1545209135 + ... + 1545210048.
It is an arithmetic number, because the mean of its divisors is an integer number (353852996568).
Almost surely, 21412321566631 is an apocalyptic number.
1412321566631 is a deficient number, since it is larger than the sum of its proper divisors (3090419641).
1412321566631 is an equidigital number, since it uses as much as digits as its factorization.
1412321566631 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3090419640.
The product of its digits is 155520, while the sum is 41.
Adding to 1412321566631 its reverse (1366651232141), we get a palindrome (2778972798772).
The spelling of 1412321566631 in words is "one trillion, four hundred twelve billion, three hundred twenty-one million, five hundred sixty-six thousand, six hundred thirty-one".
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