Base | Representation |
---|---|
bin | 11010010011101010… |
… | …00101000011110011 |
3 | 1100110021221211102222 |
4 | 31021311011003303 |
5 | 212411112144021 |
6 | 10253244431255 |
7 | 1006665135251 |
oct | 151165050363 |
9 | 40407854388 |
10 | 14123553011 |
11 | 5a98417467 |
12 | 28a1b4852b |
13 | 14410ab079 |
14 | 97da795d1 |
15 | 579ddb6ab |
hex | 349d450f3 |
14123553011 has 2 divisors, whose sum is σ = 14123553012. Its totient is φ = 14123553010.
The previous prime is 14123552981. The next prime is 14123553019. The reversal of 14123553011 is 11035532141.
14123553011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14123553011 - 210 = 14123551987 is a prime.
It is a super-2 number, since 2×141235530112 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14123553019) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7061776505 + 7061776506.
It is an arithmetic number, because the mean of its divisors is an integer number (7061776506).
Almost surely, 214123553011 is an apocalyptic number.
14123553011 is a deficient number, since it is larger than the sum of its proper divisors (1).
14123553011 is an equidigital number, since it uses as much as digits as its factorization.
14123553011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1800, while the sum is 26.
The spelling of 14123553011 in words is "fourteen billion, one hundred twenty-three million, five hundred fifty-three thousand, eleven".
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