Base | Representation |
---|---|
bin | 1100110110000111000010… |
… | …1000111100111111111011 |
3 | 1212000012211212210201100211 |
4 | 3031201300220330333323 |
5 | 3322400411004044201 |
6 | 50012205125011551 |
7 | 2655256333220524 |
oct | 315416050747773 |
9 | 55005755721324 |
10 | 14123742253051 |
11 | 4555933329922 |
12 | 1701338853bb7 |
13 | 7b5b2b537122 |
14 | 36b8427d384b |
15 | 1975ce6b4651 |
hex | cd870a3cffb |
14123742253051 has 2 divisors, whose sum is σ = 14123742253052. Its totient is φ = 14123742253050.
The previous prime is 14123742253021. The next prime is 14123742253081. The reversal of 14123742253051 is 15035224732141.
It is a balanced prime because it is at equal distance from previous prime (14123742253021) and next prime (14123742253081).
It is a cyclic number.
It is not a de Polignac number, because 14123742253051 - 29 = 14123742252539 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14123742252995 and 14123742253013.
It is not a weakly prime, because it can be changed into another prime (14123742253001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7061871126525 + 7061871126526.
It is an arithmetic number, because the mean of its divisors is an integer number (7061871126526).
Almost surely, 214123742253051 is an apocalyptic number.
14123742253051 is a deficient number, since it is larger than the sum of its proper divisors (1).
14123742253051 is an equidigital number, since it uses as much as digits as its factorization.
14123742253051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 201600, while the sum is 40.
Adding to 14123742253051 its reverse (15035224732141), we get a palindrome (29158966985192).
The spelling of 14123742253051 in words is "fourteen trillion, one hundred twenty-three billion, seven hundred forty-two million, two hundred fifty-three thousand, fifty-one".
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