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14124000000 = 2835611107
BaseRepresentation
bin11010010011101101…
…10010001100000000
31100110022210112121010
431021312302030000
5212411221000000
610253302200520
71010002006365
oct151166621400
940408715533
1014124000000
115a986a2280
1228a2123140
131441206666
1497db5446c
15579e78d50
hex349db2300

14124000000 has 504 divisors, whose sum is σ = 51738087744. Its totient is φ = 3392000000.

The previous prime is 14123999977. The next prime is 14124000013. The reversal of 14124000000 is 42141.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a self number, because there is not a number n which added to its sum of digits gives 14124000000.

It is an unprimeable number.

It is a polite number, since it can be written in 55 ways as a sum of consecutive naturals, for example, 131999947 + ... + 132000053.

It is an arithmetic number, because the mean of its divisors is an integer number (102654936).

Almost surely, 214124000000 is an apocalyptic number.

14124000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 14124000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (25869043872).

14124000000 is an abundant number, since it is smaller than the sum of its proper divisors (37614087744).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14124000000 is an frugal number, since it uses more digits than its factorization.

14124000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 167 (or 128 counting only the distinct ones).

The product of its (nonzero) digits is 32, while the sum is 12.

Adding to 14124000000 its reverse (42141), we get a palindrome (14124042141).

The spelling of 14124000000 in words is "fourteen billion, one hundred twenty-four million", and thus it is an aban number.